4y^2+16y=-19

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Solution for 4y^2+16y=-19 equation: 



4y^2+16y=-19

We move all terms to the left:

4y^2+16y-(-19)=0

We add all the numbers together, and all the variables

4y^2+16y+19=0

a = 4; b = 16; c = +19;
Δ = b2-4ac
Δ = 162-4·4·19
Δ = -48
Delta is less than zero, so there is no solution for the equation

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